Gabriel Plascencia, David Jaramillo's Basic Thermochemistry in Materials Processing PDF

By Gabriel Plascencia, David Jaramillo

ISBN-10: 3319538136

ISBN-13: 9783319538136

ISBN-10: 3319538152

ISBN-13: 9783319538150

This e-book offers the reader with a few thermochemistry notes. The goal is to supply an easy, effortless to appreciate textual content which serves as a complimentary fabric to extra advanced books. It additionally offer scholars and people starting within the box with numerous program examples utilized in various parts of fabrics processing. The e-book provides totally solved difficulties, a few mostly present in significant metallurgical operations.

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Extra resources for Basic Thermochemistry in Materials Processing

Example text

11, the heat capacity of element X is: Cp ¼ À10À6 T 3 þ 0:0003T 2 þ 0:114T À 2:092 To find the entropy, we need to use the definition: ZT DS ¼ Cp dT T 0 Remember that S = 0 at T = 0 K. 55 J mol−1 K−1, respectively. Notice that these values may change depending on the fitting of the data. 5 J mol−1 K−1, what is the entropy at 1073 °C? 63 J mol−1 K−1. Calculate the standard entropy of this metal at 750 °C, given À1  that: DHfusion; CpZn;solid ¼ 22:38 þ 10:04 Â 10À3 T J mol−1 Zn ¼ 7:28 kJ mol , −1 −1 −1 K , CpZn;liquid ¼ 31:38 J mol K .

To calculate the heat of reaction at 298 K (25 °C), it is necessary to manipulate the reactions provided: 2Al þ 32 O2 ¼ Al2 O3 C þ 12 O2 ¼ CO  J DH298 ¼ À30; 962 gAl  J DH298 ¼ À9414 gC ð1Þ ð2Þ  , we need to multiply reaction (2) by 3 and subtract reaction To obtain DH298 (1) from it: Examples of Calculations Al2 O3 þ 3C ¼ 2Al þ 3CO 29 DH298 ¼ À9414 Â 3 þ 309; 062 J To obtain the value of the heat of reaction at 298 K, it is necessary to multiply the heat contribution from reaction 1 by 54 (2 moles of aluminum are involved) and also is necessary to multiply the heat contribution from reaction 2 by 12 (3 moles of carbon react), since this reaction has already been augmented by 3; additionally, since 1 mole of alumina is reacted, the heat of reaction is expressed in terms of the mole of Al2O3.

Step 3. Multiply reaction (5) by 1/3: Fe2 O3 þ 3CO ! 2Fe þ 3CO2  DH298 ¼ À27:17 kJ We obtain the reaction we are seeking for. 17 kJ. 3 kJ/mol. Obtain an expression for DH°298 of FeO as a function of temperature and evaluate it at 800 K, using the following data: O2 ; Cp ¼ 27:73 þ 12:97 Â 10À3 T Fe; Cp ¼ 16:32 þ 28:45 Â 10À3 T FeO; Cp ¼ 52:80 þ 6:23 Â 10À3 T Solution We need to calculate the heat of reaction of the iron oxide from its constitutive elements; thus the reaction we are looking for is: Fe þ 1 O2 ¼ FeO 2 ð1Þ Examples of Calculations 27 For this reaction, its heat of formation has been already given, so  DH298;FeO ¼ À267:3 kJ=mol.

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Basic Thermochemistry in Materials Processing by Gabriel Plascencia, David Jaramillo

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